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The Official Math Thread
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Any type of question, problem or coment related with the marvellous world of mathematics is welcome.
I'm going to start with a problem I have to solve but I can't. It's the following one: Juan says to Luisa: If you give me 3 coins I will have "n" times as many as you'll have. Luisa responds: True, but if you give me "n" coins, then I will have three times what you have left. For what values of "n" are these statements true? If you know how to solve it, please help. I've already started solving it, but I can't finish it: |
the maths you wrote here aren't incorrect, but I still think the problem isn't solvable as it is stated here :(
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If I find a possible solution I'll post it here. |
actually, they say values in plural, so could it be that they want you to express n in terms of x or y? that seems unlikely to me because I guess they'd tell you explicitly if they want that, but idk
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Hell, if this ain't correct i'm gonna cry
P.S. some things are in SPanish Edit: I got confused and wrote m instead of n somewhere, i gotta change that But i think in general it's right |
yoo I got the answer. omg jesus I swear to god normally I'm way better and quicker with these things. I just thought this was a default kind of math problem that it's not
edit: what you're doing here is the right method, I haven't checked whether all the maths details are correct edit 2: so I had a look, and why are you splitting the fraction in two at some point? I think when you're saying n+13 >= 3n - 1 you're neglecting the +4 term you have |
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P.S. What I need is an Official English Beginners Thread :laughing: |
But actually in your case n+13/3n-1 can be a negative integer up to -4, so it doesn't have to be a natural number
What I had got after some algebra was: x = (7n+3)/(3-n) which needs to be a natural number, like you said. Then, since the numerator is always positive the denominator needs to be positive too, so n < 3. Then both n=1 and n=2 work we got different results though, but that may be me because I'm sloppy with algebra |
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P.S. Getting excited at a Math problem lol Edit: They can be possible solutions. I just replaced x+3=n (y-3) and 3(x-n)=y+n with the numbers obtained. If n is 3 and both Juan and Luisa have 6 coins: 6+3=3(6-3) and 3(6-3)=3+6 If n is 7 and Juan has 11 coins and Luisa 5: 11+3=7(5-3) and 3(11-7)=5+12 |
math problems are exciting. Even though this one got me feeling properly embarassed about how long it took me to realise the obvious
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no you're right, I filled it in and n=7 works so I made a typo somewhere
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And thank you very much for your help!!:love: |
my 'help' lol
https://www.memecreator.org/static/i...es/1302108.jpg I found my typo too, I lost a factor n somewhere on the way through the derivation. smgdh |
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it's the standard model <3
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:shycouch: |
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Damn, I thought this was the Official Meth Thread. I gotta get my eyes checked.
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Math: not even once.
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bruh i thought of making that same joke days ago when i first saw this thread and contemplated posting it and then said nah ... too corny
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When I have a day off I usually don't take one to save on the water bill.
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also, math is gay
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You people talkin' here about meth and I don't even know what meth is :laughing:
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Nor should you, at fourteen years of age.
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Ask your mother.
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