what if you're on the moon and you throw the ball

Since gravity is weaker, would the peak last longer?

Glad you mentioned it!

Yeah, reference frame is important.

No, you can't measure the peak as lasting for any length of time in either case.

I guess that makes sense. So if you graphed the ball being thrown on Earth and the one on the moon, both would just be different shaped parabolas?

Can’t? Or is it just not practical for basic physics?

Yep! It's just a matter of a different number for the strength of the gravitational field. The parabolic shape of the graph results because acceleration is constant.

https://www.khanacademy.org/science/...nsional-motion

That's a pretty good overview if you want to get a deeper sense of what's going on. (Admittedly I haven't watched it in years, but iirc he does a good job of explaining everything clearly without dumbing it down.) No calculus required.

EDIT:
In terms of the model of Newtonian physics, you can't, as in it's impossible.

This has been really interesting and informative. You’re a really smart dude.

Pet Sounds really is pretty damn smart but this is all high school level physics.
Are US schools really so ****ty that this is all news for you?

lol

I actually taught math in junior high for a while. Can barely add.

And I sure af didn’t take physics in high school.

I didn't learn **** in school. I didn't particularly try to.

I had to teach myself algebra when I decided to go to community college just so I could avoid all the pre algebra remedial classes.

Nah, but thanks.

In Canada, at least, it's possible to avoid physics pretty much entirely in high school, and the stuff that's taught is taught poorly. Even university science students get destroyed by first-year mechanics.