Help me please allright
 

ok i have this math problem..and i cant work with it maybe one of you can help i have a scan of it soo i need to find the length of line BC, the measuremnet of angle EAC,, arc FE, and angle, C what ive found out is AE and Db are parrell, and trinagle cbd, and cea are similar... just divde 4 by 3 to get the ratio..please help i need to pass this calass.. none of this stuff was in the book..and he wont help..he just says figure it out....and no one in ym class can do it..so please help..oh and this for perople wh have taken or are in geometry...

I think it's isosoceles, er, or however you spell it, if that helps. I'll work on it more after I get Jones soda
Edit: No. God, I forgot everything from Geometry.

It's a right triangle (because the line is tangent to the circle) and, I have a feeling you're gonna have to use sine, cosine or tangent

The answer is 6. Or 452.

^ ermm ok... umm swim its a tangent sorry i fogot to add that

i think bc might be 11

Why?
If you explain I might remember stuff.
Edit: I think BC= 21

4/(7+x)= 3/x

The radi are 3 and 4 so that's where I got 7 from. X is BC.

4x=3x+21
x=21

well obvioulsey ab= 7 +fa which is 4 is 11, and that looks as though its = to Bc

You can't judge some thing just because it looks as though its equal.

Look at the proportion I did and ask questions I you have any. You have to use trig to find the angles. And I forgot that part of geometry.

well i can pfft.maybye ill jst make my own unit of measurement up .oh and thanks swim

If I had a book I could teach myself the trig but I'm so completely stumped. I'll tell you if I have an epiphany. You don't happen to have any similar examples?

^ no..he jsut randomly handed it out and expected us to do it without any prior examples

23? 679?

Fo shizzle:

<EAC = 81.786... degrees
<C = 8.213... degrees
BC = 21
arc FE = 13.713...

yo bitch I just solved your math problem now send me Low.

it seems to me you might need to use trigonometry, i'd try working it out but i'm just too off it at the moment sorry mate, g'night.

oh wait has it been figured out? if so well done. lemme know how it was worked out so i can read about it tommorrow.

how do i know your right i didnt see any equations yo...and ill send it over aim...later tonight right now..my intermnet is having a fun 4.5 kb/s upload time

Does your teacher want to see your work? Because I promise those are the right answers.

^ yes it says please so your work

The answer is 42.

well you have to draw a line parallel to ED from B, and then where that intersects EA you have a new point, H. triangle AHB has side AH with length 1, hypotenuse AB with length 7, and side BH with length sqrt(48). you can then use the law of sines to say that sin90/7 = sinx/sqrt(48) and then solve for x. that gives you the angle measure of EAC. since you know angle E is 90, angle C is just 90 - <EAC.

erm^ with the parrel i assume you mean from linw bd to line ae?or a diagnol from b to e..sign on aim plaese... ermm and wots the fromula to find bc

allright i get it now, thank you very much for your time