6/2*(1+2)=?

Stone Birds · 04-29-2011, 09:32 PM

seven pages of this... what has the forum come to especially when i'm pretty sure we've had threads related to order of operations before

**Janszoon** · 04-29-2011, 10:18 PM

Quote:

Originally Posted by oojay

The nearly universal mathematical convention dictates the following order of operations (in order of which operators should be evaluated first):

Factorial.
Exponentiation.
Multiplication.
Division.
Addition.
Any parenthesized expressions are automatically higher ``priority'' than anything on the above list.

Considering that the site you quoted forgets to mention subtraction altogether, I don't see it as the most reliable source of information.

CanwllCorfe · 04-29-2011, 11:08 PM

Quote:

Originally Posted by oojay

6/2*(1+2) = 6/2*(3) = 6/6 = 1

By multiplying the 2 by 3, wouldn't that mean you're pairing it with the divisor? Even if you did multiplication first, shouldn't you be multiplying 6 by 3? And then getting 18, then dividing by 2? Thereby getting 9.

The 1 is unnecessary, but I wanted to add it so that everything would line up nicely in Photoshop.

midnight rain · 04-30-2011, 12:28 AM

Haha this is great, oojay just got schooled completely by canwllcorfe who makes an excellent point. Fifty bucks says he still refuses to admit he's doing it completely wrong

He appears to think the the equation reads as 6/(2*(1+2)), but its obviously how canwll's doing it. And that's only if you ignore the PEMDAS rule, which clearly puts multiplication and division on the same level.

Kirby · 04-30-2011, 02:14 AM

Quote:

Originally Posted by oojay

You can LOL all you want, but the answer is 1, not 9. Read a math book.

I'm lol'ing because I have, and the PEMDAS rule says you're wrong.

TheBig3 · 04-30-2011, 10:14 AM

Quote:

Originally Posted by CanwllCorfe

By multiplying the 2 by 3, wouldn't that mean you're pairing it with the denominator? Even if you did multiplication first, shouldn't you be multiplying 6 by 3? And then getting 18, then dividing by 2? Thereby getting 9.

The 1 is unnecessary, but I wanted to add it so that everything would line up nicely in Photoshop.

Where would you multiply 6 by 3? I got 1, and I'm not seeing your logic.

TheBig3 · 04-30-2011, 10:15 AM

Quote:

Originally Posted by Stone Birds

seven pages of this... what has the forum come to especially when i'm pretty sure we've had threads related to order of operations before

You posted in "The Worst Music You Will Ever Hear" before this. I'll stick to math.

MoonlitSunshine · 04-30-2011, 10:25 AM

I still say that it's ambiguous due to the lack of a standard convention, and that it requires an extra set of parentheses to be exact in the order of evaluation, but hey, there's not much point in beating my head against a brick wall, people can easily read my previous posts in the thread :P

CanwllCorfe · 04-30-2011, 10:37 AM

Quote:

Originally Posted by TheBig3

Where would you multiply 6 by 3? I got 1, and I'm not seeing your logic.

Well, I don't know how else to say it.

6/2 * 3. You would multiply the 6 by 3, because if you didn't, you'd be pairing it with the divisor. Which would pretty much mean you're doing 6/2 * 1/3, getting 6/6. 3, as a fraction, is 3/1. 6/2 * 3/1 = 18/2 = 9.

EDIT: Here's a picture:

You multiply the 6 by 3, getting 18. Then divide by 2.

Burning Down · 04-30-2011, 10:53 AM

Quote:

Originally Posted by CanwllCorfe

Well, I don't know how else to say it.

6/2 * 3. You would multiply the 6 by 3, because if you didn't, you'd be pairing it with the divisor. Which would pretty much mean you're doing 6/2 * 1/3, getting 6/6. 3, as a fraction, is 3/1. 6/2 * 3/1 = 18/2 = 9.

I think I get it, looking at your previous post. You're using multiplication as the main operation here, and then turning it into a simple fraction by using 6x3 as the numerator and 2x1 as the denominator. So, logically, the next step is 18/2, which of course equals 9. Right?

04-29-2011, 09:32 PM	#71 (permalink)
Stone Birds myspace.com/stonebirdies Join Date: Apr 2009 Location: Conor Oberst Was/is Here Posts: 1,401	seven pages of this... what has the forum come to especially when i'm pretty sure we've had threads related to order of operations before __________________ Silk & Tree Records //\\//\\/\\/\/\/\\\\\\\\///\/\/\/\/\\////\/\\\\\///\V //\\//\\/\\/\/\/\\\\\\\\///\/\/\/\/\\////\/\\\\\///\V soundcloud.com/stonebirds [Link removed by mod, no advertising] ... Damn those mods are always gettin ya :)

04-30-2011, 10:25 AM	#78 (permalink)
MoonlitSunshine Dat's Der Bunny! Join Date: Jul 2006 Location: Ireland Posts: 1,088	I still say that it's ambiguous due to the lack of a standard convention, and that it requires an extra set of parentheses to be exact in the order of evaluation, but hey, there's not much point in beating my head against a brick wall, people can easily read my previous posts in the thread :P __________________ "I found it eventually, at the bottom of a locker in a disused laboratory, with a sign on the door saying "Beware of the Leopard". Ever thought of going into Advertising?" - Arthur Dent

04-30-2011, 12:28 AM	#74 (permalink)
midnight rain Music Addict Join Date: Mar 2009 Posts: 1,711	Haha this is great, oojay just got schooled completely by canwllcorfe who makes an excellent point. Fifty bucks says he still refuses to admit he's doing it completely wrong He appears to think the the equation reads as 6/(2*(1+2)), but its obviously how canwll's doing it. And that's only if you ignore the PEMDAS rule, which clearly puts multiplication and division on the same level.