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I know that you went ahead and solved it the way you'd been taught, but if you noticed, in my original post, which I then quoted as it was ignored, I stated that such "order conventions" shouldn't really be taught, as they lead to such ambiguities, where people assume they're both right, when the problem is that they've both been taught a convention that a) isn't standard and b) is a nasty shortcut in the first place. If people were taught to use parentheses properly from the start, we could avoid situations like this. I agree that in a situation like that, you kinda have to guess for an answer. That, however, doesn't instantly mean that your guess is right. That's my point. I'm not saying sit on your hands and do nothing because you can't make a definite conclusion, I'm just saying that multiple answers can technically be correct as the statement is ambiguous, which you will note I stated at the start and and of my first post. |
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edit: think I'll ask my math teachers on monday. |
To be honest, I'm four years into a maths degree, and it's never been directly addressed. The only reason I see things the way I do is because it's a direct result of the way Group Theory and Real Analysis proves everything else BOMDAS/PEMDAS and the order of operations are never defined nor proved. Therefore is has to be, and evidently is, based on a non-standard convention.
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____6____ the answer is "9"2 * (1+2) if you want the answer to equal "1" then write it as ____6____ 2 * (1+2) |
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edit: not really refute. But just off really really quick research it looks like group theory is concerned with having an expansive outlook such that one term can equal different things, depending on how you look at it. I feel like there should be some sort of hint in high school math that what we're learning is not the only applicable method. |
That's some good reading the thread you did there, Neapolitan.
@Story: hmmm... kinda. In many ways, not so much refute, as expand. A lot of stuff that's taught in schools is over-simplified in order to make it easy enough to teach. Having had first hand experience teaching, I don't blame them nor the system, but it's arguable that the system could be improved without making the courses too difficult. |
For what its worth, I got 1.
I'm boggled by the philosophy that addition/subtraction and multiplication/division are interchangeable. Order of operations is something artificially created to avoid these issues. So why boggle the issue by saying These laws, for ease of things like international space travel, will be iron clad...except for these parts here. Do this however the **** ya want. That part I'm lost on. its 1. |
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Left Right a/b*(c+d) =a÷b×(c+d) If the equation was this: ____a____ b * (c+d) it would be a÷[b×(c+d)] Quote:
Burning Down is right QED |
9.
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Yeah I just read the title, did the problem, got 9.
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Or 1 (if you do it the way you were taught your entire life, and the way that everyone you have ever interacted with in any mathematical environment have always done it).
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No that's not the case. Left to Right as BD brought up still applies. What I'm trying to say the way it is written on the computer in a single line is limited than how it would be written on paper. If you looking at it as 6/2*(1+2) equals ____6____ 2 * (1+2) then you are going to run into some problem. If you understand that when the "/" line is used, only divided the number underneath divides the number on top, in this case 6/2 means 6 divided by 2, (only 2 not the rest of the equation), 6/2 = 6÷2 |
The aliens got to your head. I learned that multiplication and division are equal. I Googled "order of operations", clicked every link on the first page.
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6/2*(3)=? Now it's division and multiplication, so left to right. 6/2*3=? 3*3=9 I'm sorry, but I've literally never heard anyone ever say one was more important than the other. I even Googled the problem, and Google calculator was the only thing that came up. It told me the answer was 9. |
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I got a 94 in Algebra II bro. I can do anything.
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Put me squarely in the "9" camp please.
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But yes, it's 9. |
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Yup! I say it could probably be locked now.
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You say that multiplication and division both bear equal precedence between one another, therefore, in a complex equation involving both multiplication and division, one should simply operate from left to right. My disagreement, which I supported with numerous and equally credible links, says that multiplication ALWAYS takes precedence over division, just as addition ALWAYS takes precedence over subtraction, per the PEMDAS method of operation that was cited in my links, and has been taught to me my entire life, with which Big3 also agreed with. We both cited sources that are completely conflicting with one another as far as the precedence involved within the order of operations goes. One source says A, the other says B. Both are not correct, but both are not wrong either. As MoonlitSunshine has said, the equation is too ambiguous at this point to be correctly solved using either method of operation. Quote:
But if asked to explain why one method of operation would be superior to the other, I would posit this: Addition is positive, meaning that you are adding something to the number. Subtraction is negative, meaning that you are taking something away from the number. Rather than a left to right interpretation for a method of operation between the two, one should use a Positive>Negative order of operation, as a positive number > a negative number. Do the positive (Addition) first, and the negative (Subtraction) second. Thusly, Multiplication should be considered the "positive" operation, as the exponents are positive, and Division should be considered the "negative" operation, as it is the inverse of multiplacation, meaning that the exponent is negative. As all sources have stated, exponents takes precedence over ALL other operations. Per the transitive property, Multiplication (utilizing a positive exponent) therefore takes precedence over Division (utilizing in essence a negative exponent). With that being said, and Multiplication being the positive operation, and Division being the negative operation, it is easy to come to the result that: 6/2*(1+2) = 6/2*(3) = 6/6 = 1 |
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I think, oojay, that there are a handful of teachers simply forgetting to tell some generations of students about that important piece of info, that they share precedence and go left to right. 9 |
seven pages of this... what has the forum come to especially when i'm pretty sure we've had threads related to order of operations before
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http://i392.photobucket.com/albums/p...g?t=1304136614 The 1 is unnecessary, but I wanted to add it so that everything would line up nicely in Photoshop. |
Haha this is great, oojay just got schooled completely by canwllcorfe who makes an excellent point. Fifty bucks says he still refuses to admit he's doing it completely wrong
He appears to think the the equation reads as 6/(2*(1+2)), but its obviously how canwll's doing it. And that's only if you ignore the PEMDAS rule, which clearly puts multiplication and division on the same level. |
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http://edu.glogster.com/media/5/25/75/42/25754207.jpg |
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I still say that it's ambiguous due to the lack of a standard convention, and that it requires an extra set of parentheses to be exact in the order of evaluation, but hey, there's not much point in beating my head against a brick wall, people can easily read my previous posts in the thread :P
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EDIT: Here's a picture: http://i392.photobucket.com/albums/p...fe/mathtos.jpg You multiply the 6 by 3, getting 18. Then divide by 2. |
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